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100x^2-176x-528=0
a = 100; b = -176; c = -528;
Δ = b2-4ac
Δ = -1762-4·100·(-528)
Δ = 242176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{242176}=\sqrt{256*946}=\sqrt{256}*\sqrt{946}=16\sqrt{946}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-176)-16\sqrt{946}}{2*100}=\frac{176-16\sqrt{946}}{200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-176)+16\sqrt{946}}{2*100}=\frac{176+16\sqrt{946}}{200} $
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